2020/03/26

[zerojudge] b331: NOIP2013 2.表达式求值

import sys
from functools import reduce
import operator

def fn(x):
    x = [int(c) for c in x.split('*')]
    return(reduce(operator.mul, x, 1))

s = sys.stdin.readline().strip().split('+')
print(sum([fn(x) for x in s])%10000)

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